Một hợp chất B có công thức M2X
Giải chi tiết: \(\left\{ \begin{gathered} 2.(2{p_M} + {n_M}) + (2{p_X} + {n_X}) = 116\,\,\,\,\,\,\,\,\,\,\,\,\, \hfill \\ (2.2{p_M} + 2{p_X}) - (2{n_M} + {n_X}) = 36\,\,\,\,\,\,\,\,\,\,\, \hfill \\ ({p_X} + {n_X}) - ({p_M} + {n_M}) = 9\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \hfill \\ (2{p_X} + {n_X} + 2) - (2{p_M} + {n_M} - 1) = 17\,\,\,\,\, \hfill \\ \end{gathered} \right.\) => \(\left\{ \begin{gathered} 2.(2{p_M} + {n_M}) + (2{p_X} + {n_X}) = 116\,\,\,\,\,\,\,\,\,\,\,\,\,(1) \hfill \\ (2.2{p_M} + 2{p_X}) - (2{n_M} + {n_X}) = 36\,\,\,\,\,\,\,\,\,\,\,\,(2) \hfill \\ ({p_X} + {n_X}) - ({p_M} + {n_M}) = 9\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(3) \hfill \\ (2{p_X} + {n_X}) - (2{p_M} + {n_M}) = 14\,\,\,\,\,(4) \hfill \\ \end{gathered} \right.\) Lấy (1)+(2) => 8pM + 4pX = 152 Lấy (4)-(3) => pX - pM = 5 \(\left\{ \begin{gathered} 8{p_M} + 4{p_X} = 184 \hfill \\ {p_X} - {p_M} = 5 \hfill \\ \end{gathered} \right. \to \left\{ \begin{gathered} {p_M} = 11 \hfill \\ {p_X} = 16 \hfill \\ \end{gathered} \right.\) Đáp án B |