What least number must be subtracted from 1294 so that the result leave no remainder when divided by 9 11 13 in each case?

  • Aptitude
  • Number series


A) 2

B) 3

C) 1

D) 4

Correct Answer:

C) 1

Description for Correct answer:
Remaining Number LCM \( \Large (9,11,13)+6=1293 \)

Least Number\( \Large =1294-1293=1 \)

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What least number must be subtracted from 1294 so that the result leave no remainder when divided by 9 11 13 in each case?

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Updated On: 27-06-2022

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Text Solution

2314

Answer : C

Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

646904745

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वह न्यूनतम संख्या कोजिए जिसे 1294 में से घटाने पर और फिर शेष बची संख्या को 9, 11, 13 तीनों से भाग देने पर प्रत्येक बर 6 शेष बचे ?

643753778

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1294 में से कौन-सी न्यूनतम संख्या को घटाई जाए कि जब परिणामी संख्या को 9, 11, 13 से भाग दिया जाए तो प्रत्येक स्थिति में समान शेषफल 6 आए?

643430953

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2:30

The least number which when divided by 4, 6, 8 and 9 leave zero remainder in each case and when divided by 13 leaves a remainder of 7 is:

646927328

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1:27

The least number which wehn divided by 4, 6, 8 and 9 leaves zero remainder in each case and when divided by 13 leaves a remainder of 7 is :

646462974

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2:46

The least number which should be subtracted from 1936 so that the remainder, which when divided by 9, 10 and 15 leaves the remainder 7 in each cases is

646301771

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7.6 K

1:55

What is the least number which when divided by 4,6,8 and 9 leaves zero remainder in each case but when divided by 13 leaves a remainder of 7?

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What least number must be subtracted from 1294 so that the result leave no remainder when divided by 9 11 13 in each case?

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What least number must be subtracted from 1294 so that the remainder when divided?

Correct Option: B On dividing 1294 by 1287, the remainder is 7 . ∴ 1 must be subtracted from 1294, so that 1293 when divided by 9, 11, 13 leaves in each case the same remainder 6 .

Which least number must be subtracted from 1294 so that the remainder when divided by 9 11 13 will leave in each case the same remainder 6?

LCM of 9,11,13 is 1287. On Dividing 1294 with 1287, we get remainder as 7, Now to get remainder 6, 1 is to be deducted from 1294 so that 1293 when divided by 9,11,13 leaves 6 as remainder. 24.

What least number must be subtracted from 319 so that the result leave no remainder when divided by 5 7 9 in each case?

4 is the least number must be subtracted from 319 so that the result leave the same remainder when divided by 5, 7, 9 in each case.

What least number must be subtracted from 13601 so that the remainder is divisible by 87?

So we do, ⇒ 13601 ÷ 87 will give you the quotient 156 and remainder 29. So, 29 is the least number subtracted from 13601 to get the number which is completely divisible by 87.

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