How many different words can be formed from the letter of the word combine so that vowels always remain together?

Solution

There are 7 letters in the word. STRANGE, including 2 vowels (A, E) and 5 consonants (S, T, R, N, G). (i) Considering 2 vowels as one letter, we have 6 letters which can be arranged in 6P6 = 6! ways A, E can be put together in 2! ways. Hence, required number of words = 6!×2! = 6×5×4×3×2×1×2 = 720×2 = 1440. (ii) The total number of words formed by.: using all the letters of the words 'STRANGE'is 7P7=7! = 7×6×5×4×3×2×1 = 5040. So, the total number of words in which vowels are never together = Total number of words - number of words in which vowels are always together = 5040-1440 =3600 (iii) There are 7 letters in the word 'STRANGE', out of these letters 'A' and `E' are the vowels. There are 4 odd places in the word 'STRANGE'. The two vowels can be arrangd in 4P2 ways. The remaining 5 consonants can be arranged among themselves in 5P5 ways. The total number of arrangements. = 4P2×5P5 = 4!2!×5! = 1440

How many different words can be formed from the letter of the word combine so that vowels always remain together?

COMBINE HAS 7 LETTERS in which C,M,B,N R 4 CONSONANTS ND O,I,E R 3 VOWELS

1) OIE, C,M,B,N CAN BE ARRANGED 5!=120 ways

bt vowels can be arranged among themselves=3!=6 ways

total no.of ways=120*6=720

How many different words can be formed from the letter of the word combine so that vowels always remain together?

COMBINE HAS 7 LETTERS in which C,M,B,N R 4 CONSONANTS ND O,I,E R 3 VOWELS

1) OIE, C,M,B,N CAN BE ARRANGED 5!=120 ways

bt vowels can be arranged among themselves=3!=6 ways

total no.of ways=120*6=720

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Ans. (i) 720

       (ii) 1440

        (iii) 576

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